x/(x^2+2x-3)+1/(1-2x+x^2)

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Solution for x/(x^2+2x-3)+1/(1-2x+x^2) equation: 


D( x )

x^2+2*x-3 = 0

x^2-(2*x)+1 = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

DELTA = 2^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)

x = 1 or x = -3

x^2-(2*x)+1 = 0

x^2-(2*x)+1 = 0

x^2-2*x+1 = 0

x^2-2*x+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

x = 2/(1*2)

x = 1 or x = 1

x in (-oo:-3) U (-3:1) U (1:+oo)

x/(x^2+2*x-3)+1/(x^2-(2*x)+1) = 0

x/(x^2+2*x-3)+1/(x^2-2*x+1) = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

DELTA = 2^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)

x = 1 or x = -3

(x+3)*(x-1) = 0

x^2-2*x+1 = 0

x^2-2*x+1 = 0

x^2-2*x+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

x = 2/(1*2)

x = 1 or x = 1

(x-1)^2 = 0

x/((x+3)*(x-1))+1/((x-1)^2) = 0

(x*(x-1))/((x+3)*(x-1)^2)+(1*(x+3))/((x+3)*(x-1)^2) = 0

x*(x-1)+1*(x+3) = 0

x^2+3 = 0

(x^2+3)/((x+3)*(x-1)^2) = 0

(x^2+3)/((x+3)*(x-1)^2) = 0 // * (x+3)*(x-1)^2

x^2+3 = 0

1*x^2 = -3 // : 1

x^2 = -3

x belongs to the empty set

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